What would be the interface ID of an IPv6 enabled interface with a MAC address of 1C-6F-65-C2-BD-F8 when the interface ID is generated by using the EUI-64 process?

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Multiple Choice

What would be the interface ID of an IPv6 enabled interface with a MAC address of 1C-6F-65-C2-BD-F8 when the interface ID is generated by using the EUI-64 process?

Explanation:
The interface ID of an IPv6 address generated using the EUI-64 process is derived from the device's MAC address. To generate the interface ID from a MAC address, the following steps are taken: 1. Convert the MAC address into a binary format. 2. Split the MAC address into two halves. 3. Insert "FFFE" in between the two halves of the MAC address. This creates a 64-bit interface ID. 4. Modify the 7th bit (the universal/local bit) of the first byte. If the bit is 0 (indicating that the address is globally unique), it is changed to 1 to signify a locally administered address. Given the MAC address of 1C-6F-65-C2-BD-F8: 1. Convert it to binary: - 1C = 00011100 - 6F = 01101111 - 65 = 01100101 - C2 = 11000010 - BD = 10111101 - F8 = 11111000 2. The first half (1C-6F-65) becomes: - 00011100 011

The interface ID of an IPv6 address generated using the EUI-64 process is derived from the device's MAC address. To generate the interface ID from a MAC address, the following steps are taken:

  1. Convert the MAC address into a binary format.

  1. Split the MAC address into two halves.

  2. Insert "FFFE" in between the two halves of the MAC address. This creates a 64-bit interface ID.

  3. Modify the 7th bit (the universal/local bit) of the first byte. If the bit is 0 (indicating that the address is globally unique), it is changed to 1 to signify a locally administered address.

Given the MAC address of 1C-6F-65-C2-BD-F8:

  1. Convert it to binary:

  • 1C = 00011100

  • 6F = 01101111

  • 65 = 01100101

  • C2 = 11000010

  • BD = 10111101

  • F8 = 11111000

  1. The first half (1C-6F-65) becomes:
  • 00011100 011
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